How many moles of ethyl bromide are required | vedclass

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(B) The reaction of ethylamine $(CH_3CH_2NH_2)$ with ethyl bromide $(C_2H_5Br)$ is an example of ammonolysis/alkylation of amines.Step $1$: Ethylamine

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$2$

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(B) The reaction of ethylamine $(CH_3CH_2NH_2)$ with ethyl bromide $(C_2H_5Br)$ is an example of ammonolysis/alkylation of amines.Step $1$: Ethylamine reacts with $1 \ mole$ of ethyl bromide to form diethylamine $(CH_3CH_2NHCH_2CH_3)$.$CH_3CH_2NH_2 + C_2H_5Br \rightarrow (CH_3CH_2)_2NH + HBr$Step $2$: Diethylamine further reacts with another $1 \ mole$ of ethyl bromide to form $N,N$-diethylethanamine (triethylamine,$(CH_3CH_2)_3N$).$(CH_3CH_2)_2NH + C_2H_5Br \rightarrow (CH_3CH_2)_3N + HBr$Total moles of ethyl bromide required = $1 + 1 = 2 \ moles$.

How many moles of ethyl bromide are required for the formation of $1 \ mole$ of $N,N$-diethylethanamine from ethylamine?

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