How many moles of hydrogen gas are liberated | vedclass

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(B) The chemical reaction between ethyl alcohol $(C_2H_5OH)$ and sodium metal $(Na)$ is:$2C_2H_5OH + 2Na \rightarrow 2C_2H_5ONa + H_2 \uparrow$From th

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(B) The chemical reaction between ethyl alcohol $(C_2H_5OH)$ and sodium metal $(Na)$ is:$2C_2H_5OH + 2Na ightarrow 2C_2H_5ONa + H_2 \uparrow$From the balanced chemical equation, $2 	ext{ moles}$ of ethyl alcohol produce $1 	ext{ mole}$ of hydrogen gas $(H_2)$.Therefore, $6 	ext{ moles}$ of ethyl alcohol will produce:$\frac{1}{2} 	imes 6 = 3 	ext{ moles}$ of $H_2$ gas.Thus, the correct option is $B$.

How many moles of hydrogen gas are liberated when $6 \text{ moles}$ of ethyl alcohol reacts with sodium metal?

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