How many numbers of four digits can be formed | vedclass

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(C) The total number of available digits is $n = 5$ $(1, 2, 3, 4, 5)$.We need to form a number with $r = 4$ digits.Since the order of digits matters i

Vedclass · Accepted Answer

$120$

Vedclass · Answer

(C) The total number of available digits is $n = 5$ $(1, 2, 3, 4, 5)$.We need to form a number with $r = 4$ digits.Since the order of digits matters in forming a number,we use the permutation formula $P(n, r) = \frac{n!}{(n-r)!}$.Substituting the values: $P(5, 4) = \frac{5!}{(5-4)!} = \frac{5!}{1!} = 5 	imes 4 	imes 3 	imes 2 = 120$.Therefore,$120$ four-digit numbers can be formed.

How many numbers of four digits can be formed with the digits $1, 2, 3, 4$ and $5$?

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