How many of the following lanthanide elements | vedclass

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(A) The lanthanide elements that exhibit the $+4$ oxidation state are $Ce$ $(Z=58)$,$Pr$ $(Z=59)$,$Nd$ $(Z=60)$,$Tb$ $(Z=65)$,and $Dy$ $(Z=66)$. Among

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$5$

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(A) The lanthanide elements that exhibit the $+4$ oxidation state are $Ce$ $(Z=58)$,$Pr$ $(Z=59)$,$Nd$ $(Z=60)$,$Tb$ $(Z=65)$,and $Dy$ $(Z=66)$. Among the given elements: $1$. $Ce$ $(4f^1 5d^1 6s^2)$ forms $Ce^{4+}$ $(4f^0)$ which is stable due to noble gas configuration. $2$. $Pr$ $(4f^3 6s^2)$ can exhibit $+4$ state. $3$. $Nd$ $(4f^4 6s^2)$ can exhibit $+4$ state. $4$. $Tb$ $(4f^9 6s^2)$ forms $Tb^{4+}$ $(4f^7)$ which is stable due to half-filled $f$-orbital. $5$. $Dy$ $(4f^{10} 6s^2)$ can exhibit $+4$ state. Thus,there are $5$ elements in the given list that exhibit the $+4$ oxidation state.

List-$I$	List-$II$
$A$. Titanium	$I$. Non-metal
$B$. Fluorine	$II$. Transition metal
$C$. Tellurium	$III$. Lanthanoid
$D$. Dysprosium	$IV$. Metalloid

How many of the following lanthanide elements exhibit $+4$ oxidation state?
$Ce, Pr, Nd, Pm, Sm, Eu, Gd, Tb, Dy$

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How many of the following lanthanide elements exhibit $+4$ oxidation state? $Ce, Pr, Nd, Pm, Sm, Eu, Gd, Tb, Dy$