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(A) For an octahedral complex of the type $[M(AB)(CD)ef]$,where $AB$ and $CD$ are unsymmetrical bidentate ligands and $e, f$ are monodentate ligands,t

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$20$

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(A) For an octahedral complex of the type $[M(AB)(CD)ef]$,where $AB$ and $CD$ are unsymmetrical bidentate ligands and $e, f$ are monodentate ligands,the total number of geometrical isomers is $20$.Each geometrical isomer is chiral because the complex lacks a plane of symmetry and a center of inversion.Since each geometrical isomer exists as a pair of enantiomers (a $d$ and $l$ form),the total number of enantiomeric pairs is equal to the total number of geometrical isomers.Therefore,there are $20$ pairs of enantiomers possible.

How many pairs of enantiomers are possible for the following complex compound,$[M(AB)(CD)ef]^{n \pm}$ (where $AB, CD$ are unsymmetrical bidentate ligands,and $e, f$ are monodentate ligands)?

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