How many stereoisomers are possible for 2-hyd | vedclass

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(C) The molecule $2$-hydroxycyclopentanethiol has two chiral centers at the $C_1$ and $C_2$ positions of the cyclopentane ring.Since the two chiral ce

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$4$

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(C) The molecule $2$-hydroxycyclopentanethiol has two chiral centers at the $C_1$ and $C_2$ positions of the cyclopentane ring.Since the two chiral centers are attached to different groups (one to $-OH$ and one to $-SH$),the molecule does not possess a plane of symmetry in any configuration.The number of stereoisomers for a molecule with $n$ chiral centers and no internal symmetry is given by $2^n$.Here,$n = 2$,so the number of stereoisomers is $2^2 = 4$.These consist of two pairs of enantiomers: $(1R, 2R)$,$(1S, 2S)$,$(1R, 2S)$,and $(1S, 2R)$.

How many stereoisomers are possible for $2$-hydroxycyclopentanethiol?

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