How many times does the electron go round the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The frequency of revolution $f$ of an electron in the $n^{th}$ orbit is given by $f = \frac{v_n}{2\pi r_n}$.For the first Bohr orbit $(n=1)$ of a

Vedclass · Accepted Answer

$6.57 	imes 10^{15}$

Vedclass · Answer

(D) The frequency of revolution $f$ of an electron in the $n^{th}$ orbit is given by $f = \frac{v_n}{2\pi r_n}$.For the first Bohr orbit $(n=1)$ of a hydrogen atom,the velocity $v_1 = 2.18 	imes 10^6 \, m/s$ and the radius $r_1 = 0.529 	imes 10^{-10} \, m$.Substituting these values:$f = \frac{2.18 	imes 10^6}{2 	imes 3.14159 	imes 0.529 	imes 10^{-10}}$$f \approx \frac{2.18 	imes 10^6}{3.324 	imes 10^{-10}}$$f \approx 6.56 	imes 10^{15} \, Hz$.Thus,the electron completes approximately $6.57 	imes 10^{15}$ revolutions per second.

How many times does the electron go round the first Bohr orbit in a second?

Similar Questions

An electron rotates in a circle around a nucleus having positive charge $Ze$. The correct relation between the total energy $(E)$ of the electron and its potential energy $(U)$ is:

What is the moment of inertia of the electron moving in the second Bohr orbit of a hydrogen atom? ($h=$ Planck's constant,$m=$ mass of electron,$\varepsilon_0=$ permittivity of free space,$e=$ charge on electron)

According to Bohr's model, the highest kinetic energy is associated with the electron in the

When an electron jumps from the orbit $n=2$ to $n=4$,the wavelength of the radiation absorbed will be ($R$ is Rydberg's constant).

If the energy in the first excited state in a hydrogen atom is $23.8 \, eV$,then the potential energy of a hydrogen atom in the ground state can be assumed to be ....... $eV$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module