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(A) The number of types of gametes produced by an individual is determined by the formula $2^n$,where $n$ is the number of heterozygous gene pairs.For

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(A) The number of types of gametes produced by an individual is determined by the formula $2^n$,where $n$ is the number of heterozygous gene pairs.For the genotype $AAbb$,the gene pairs are $AA$ (homozygous dominant) and $bb$ (homozygous recessive).Since there are no heterozygous pairs,$n = 0$.Therefore,the number of types of gametes $= 2^0 = 1$.The only gamete produced is $Ab$.

How many types of gametes can be produced by an individual with the genotype $AAbb$?

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