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(C) The atomic number of cobalt $(Co)$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the $[CoF_6]^{3-}$ complex,the oxidation s

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$4$

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(C) The atomic number of cobalt $(Co)$ is $27$. The electronic configuration of $Co$ is $[Ar] 3d^7 4s^2$.In the $[CoF_6]^{3-}$ complex,the oxidation state of $Co$ is $x + 6(-1) = -3$,so $x = +3$.The electronic configuration of $Co^{3+}$ is $[Ar] 3d^6$.In the $3d$ subshell,the $6$ electrons are distributed as follows: one orbital is doubly occupied,and the remaining four orbitals are singly occupied.Therefore,there are $4$ unpaired electrons present in the $Co^{3+}$ ion prior to hybridization.

List-$I$ (Complexes)	List-$II$ (Hybridisation)
$A$. $[Ni(CO)_4]$	$I$. $sp^3$
$B$. $[Cu(NH_3)_4]^{2+}$	$II$. $dsp^2$
$C$. $[Fe(NH_3)_6]^{2+}$	$III$. $sp^3d^2$
$D$. $[Fe(H_2O)_6]^{2+}$	$IV$. $d^2sp^3$

How many unpaired electrons are present in the cobalt ion in the $+3$ oxidation state prior to hybridization in the $[CoF_6]^{3-}$ complex ion?

Similar Questions

The number of unpaired electrons in $[NiCl_{4}]^{2-}$, $Ni(CO)_{4}$ and $[Cu(NH_{3})_{4}]^{2+}$ respectively are

What is the number of unpaired electrons in $[Co(NH_3)_6]^{3+}$ complex?

Both $[Ni(CO)_4]$ and $[Ni(CN)_4]^{2-}$ are diamagnetic. The types of hybridisation of $Ni$ in these complexes are . . . . . . and . . . . . . respectively.

Match List-$I$ with List-$II$:

List-$I$ (Complexes) List-$II$ (Hybridisation)

$A$. $[Ni(CO)_4]$ $I$. $sp^3$

$B$. $[Cu(NH_3)_4]^{2+}$ $II$. $dsp^2$

$C$. $[Fe(NH_3)_6]^{2+}$ $III$. $sp^3d^2$

$D$. $[Fe(H_2O)_6]^{2+}$ $IV$. $d^2sp^3$

Which of the following pairs of structure and magnetic properties is correct for the tetracyanonickelate$(II)$ ion?

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