How does the maximum kinetic energy of a phot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of a photoelectron is given by: $K_{max} = h
u - \Phi_0$ wh

Vedclass · Accepted Answer

It depends linearly on frequency; it does not depend on the intensity of incident light.

Vedclass · Answer

(A) According to Einstein's photoelectric equation,the maximum kinetic energy $(K_{max})$ of a photoelectron is given by: $K_{max} = h
u - \Phi_0$ where $h$ is Planck's constant,$
u$ is the frequency of incident radiation,and $\Phi_0$ is the work function of the metal. $1$. Dependence on frequency: The equation shows that $K_{max}$ increases linearly with the frequency $(
u)$ of the incident radiation. $2$. Independence: $K_{max}$ does not depend on the intensity of the incident radiation,as intensity only affects the number of photoelectrons emitted per second,not their individual kinetic energies.

How does the maximum kinetic energy of a photoelectron depend on the frequency of incident radiation? On which factors does it not depend?

Similar Questions

When a certain metal surface is illuminated with light of wavelength $\lambda$,the stopping potential is $V$. When the same surface is illuminated by light of wavelength $2\lambda$,the stopping potential is $\frac{V}{3}$. The threshold wavelength for the surface is:

If the work function of a metal is $\phi$ and the frequency of the incident light is $\nu$,there is no emission of photoelectrons if:

If the frequency of light in a photoelectric experiment is doubled,the stopping potential will

In a photoelectric cell,the wavelength of incident light is changed from $4000 \, \mathring{A}$ to $3600 \, \mathring{A}$. The change in stopping potential will be ............. $V$.

When a metallic surface is illuminated with light of wavelength $\lambda$,the stopping potential is $x \ V$. When the same surface is illuminated by light of wavelength $2 \lambda$,the stopping potential is $\frac{x}{3} \ V$. The threshold wavelength for the metallic surface is ..........

Vedclass Test Series

Exam Paper Generator

Online Exam Module