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(B) The energy released per fission of a $U^{235}$ nucleus is approximately $200 \, MeV$.First,calculate the number of atoms in $1 \, kg$ of $U^{235}$

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$8.2 	imes 10^{13} \, J$

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(B) The energy released per fission of a $U^{235}$ nucleus is approximately $200 \, MeV$.First,calculate the number of atoms in $1 \, kg$ of $U^{235}$.The number of atoms $N = (m / M) 	imes N_A$,where $m = 1000 \, g$,$M = 235 \, g/mol$,and $N_A = 6.023 	imes 10^{23} \, atoms/mol$.$N = (1000 / 235) 	imes 6.023 	imes 10^{23} \approx 2.56 	imes 10^{24} \, atoms$.The total energy $E = N 	imes 200 \, MeV$.$E = 2.56 	imes 10^{24} 	imes 200 	imes 1.6 	imes 10^{-13} \, J$.$E \approx 8.2 	imes 10^{13} \, J$.

How much energy is produced by the fission of $1\, kg$ of uranium?

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