How much oxygen is required for complete comb | vedclass

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(B) The balanced chemical equation for the combustion of ethene $(C_2H_4)$ is: $C_2H_4 + 3O_2 	o 2CO_2 + 2H_2O$ Calculate the number of moles of ethe

Vedclass · Accepted Answer

$1.92$

Vedclass · Answer

(B) The balanced chemical equation for the combustion of ethene $(C_2H_4)$ is: $C_2H_4 + 3O_2 	o 2CO_2 + 2H_2O$ Calculate the number of moles of ethene: $n_{C_2H_4} = \frac{	ext{mass}}{	ext{molar mass}} = \frac{560 \ g}{28 \ g/mol} = 20 \ mol$ From the stoichiometry,$1 \ mol$ of $C_2H_4$ requires $3 \ mol$ of $O_2$. Therefore,$20 \ mol$ of $C_2H_4$ requires: $n_{O_2} = 3 	imes 20 \ mol = 60 \ mol$ Calculate the mass of oxygen: $w_{O_2} = n_{O_2} 	imes 	ext{molar mass of } O_2 = 60 \ mol 	imes 32 \ g/mol = 1920 \ g$ Convert to $kg$: $1920 \ g = 1.92 \ kg$

How much oxygen is required for complete combustion of $560 \ g$ of ethene? ................. $kg$

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