How much work is done in moving a charge of 2 | vedclass

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(B) Given: Charge $q = 2 \ C$,Initial potential $V_1 = 118 \ V$,Final potential $V_2 = 128 \ V$.We know that the potential difference $V$ is defined a

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$20$

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(B) Given: Charge $q = 2 \ C$,Initial potential $V_1 = 118 \ V$,Final potential $V_2 = 128 \ V$.We know that the potential difference $V$ is defined as the work done $W$ per unit charge $q$,i.e.,$V = W / q$.Therefore,the work done $W = q 	imes (V_2 - V_1)$.Substituting the values: $W = 2 	imes (128 - 118) = 2 	imes 10 = 20 \ J$.Thus,the total work done is $20 \ J$.

How much work is done in moving a charge of $2 \ C$ from a point at $118 \ V$ to a point at $128 \ V$ (in $J$)?

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