How will you differentiate 0.50 mol Na_2CO_3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) $0.50 \ mol$ $Na_2CO_3$ represents the absolute amount of substance (number of moles) of $Na_2CO_3$ present.$0.50 \ M$ $Na_2CO_3$ represents the m

Vedclass · Accepted Answer

$0.50 \ mol$ is amount of substance,$0.50 \ M$ is molar concentration.

Vedclass · Answer

(B) $0.50 \ mol$ $Na_2CO_3$ represents the absolute amount of substance (number of moles) of $Na_2CO_3$ present.$0.50 \ M$ $Na_2CO_3$ represents the molar concentration (molarity),which is defined as the number of moles of solute present in $1 \ L$ of solution.Therefore,$0.50 \ M$ $Na_2CO_3$ means $0.50 \ mol$ of $Na_2CO_3$ is dissolved in $1 \ L$ of solution.

How will you differentiate $0.50 \ mol$ $Na_2CO_3$ and $0.50 \ M$ $Na_2CO_3$?

Similar Questions

Number of atoms in $24 \ g$ of $He$ is ............ $N_A$

The total number of protons in $10 \ g$ of calcium carbonate is $(N_0 = 6.023 \times 10^{23})$

The density of water is $1 \, g/mL$. What is the volume occupied by $1$ molecule of water :-

If $500 \ mL$ of $NH_3$ gas at $STP$ contains $6.0 \times 10^{21}$ molecules,how many molecules will $100 \ mL$ of $CO_2$ gas contain at $STP$?

How many moles of nitrogen atoms are present in $8 \ g$ of ammonium nitrate (in $mol$)?

Vedclass Test Series

Exam Paper Generator

Online Exam Module