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(D) The hydrocarbon $(A)$ is methane $(CH_4)$.$CH_4$ reacts with $Br_2$ in the presence of light $(hv)$ via free radical substitution to form methyl b

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$CH_4$

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(D) The hydrocarbon $(A)$ is methane $(CH_4)$.$CH_4$ reacts with $Br_2$ in the presence of light $(hv)$ via free radical substitution to form methyl bromide $(CH_3Br)$.$CH_4 + Br_2 \xrightarrow{hv} CH_3Br + HBr$Methyl bromide $(CH_3Br)$ undergoes the Wurtz reaction in the presence of sodium $(Na)$ and dry ether to form ethane $(CH_3-CH_3)$.$2CH_3Br + 2Na \xrightarrow{	ext{dry ether}} CH_3-CH_3 + 2NaBr$Ethane $(CH_3-CH_3)$ is a gaseous hydrocarbon containing two carbon atoms,which is less than four carbon atoms.

Hydrocarbon $(A)$ reacts with bromine by substitution to form an alkyl bromide,which by Wurtz reaction is converted to a gaseous hydrocarbon containing less than four carbon atoms. $(A)$ is

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