Identify X in _{16}S^{32} + X to _{15}P^{30} | vedclass

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(B) To identify $X$,we apply the law of conservation of mass number and atomic number.Let $X$ be represented as $_{Z}A^{M}$.For mass number: $32 + M =

Vedclass · Accepted Answer

$_{1}D^{2}$

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(B) To identify $X$,we apply the law of conservation of mass number and atomic number.Let $X$ be represented as $_{Z}A^{M}$.For mass number: $32 + M = 30 + 4 \implies 32 + M = 34 \implies M = 2$.For atomic number: $16 + Z = 15 + 2 \implies 16 + Z = 17 \implies Z = 1$.Thus,$X$ is $_{1}X^{2}$,which corresponds to the deuteron $_{1}D^{2}$ (or $_{1}H^{2}$).

Identify $X$ in $_{16}S^{32} + X \to _{15}P^{30} + _{2}He^{4}$.

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