Identify A in the following reaction.A xright | vedclass

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(B) The reaction sequence is as follows:$1$. $A$ reacts with lithium amide $(LiNH_2)$ to form ethynyl lithium $(HC \equiv CLi)$. This indicates that $

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Ethyne

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(B) The reaction sequence is as follows:$1$. $A$ reacts with lithium amide $(LiNH_2)$ to form ethynyl lithium $(HC \equiv CLi)$. This indicates that $A$ must be ethyne $(HC \equiv CH)$,as terminal alkynes react with strong bases like lithium amide to form acetylides.$2$. Ethynyl lithium $(HC \equiv CLi)$ then reacts with bromoethane $(CH_3CH_2Br)$ via an $S_N2$ reaction to form but-$1$-yne $(HC \equiv C-CH_2CH_3)$.Therefore,$A$ is ethyne.

Identify $A$ in the following reaction.
$A$ $\xrightarrow{\text{Lithium amide}} \text{Ethynyl lithium}$ $\xrightarrow{\text{Bromoethane}} \text{but-}1\text{-yne}$

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Identify $A$ in the following reaction.$A$ $\xrightarrow{\text{Lithium amide}} \text{Ethynyl lithium}$ $\xrightarrow{\text{Bromoethane}} \text{but-}1\text{-yne}$