Identify X and Y in the following reactions:C | vedclass

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(D) The partial oxidation of methane $(CH_4)$ under different conditions yields different products.$1$. When $CH_4$ is oxidized with $O_2$ in the pres

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$CH_2O, CH_3OH$

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(D) The partial oxidation of methane $(CH_4)$ under different conditions yields different products.$1$. When $CH_4$ is oxidized with $O_2$ in the presence of $Mo_2O_3$ at high temperature $(\Delta)$,it forms formaldehyde ($HCHO$ or $CH_2O$):$CH_4 + O_2 \xrightarrow{Mo_2O_3 / \Delta} HCHO + H_2O$Thus,$X = CH_2O$.$2$. When $CH_4$ is oxidized with $O_2$ in the presence of $Cu$ at $523 \ K$ and $100 \ atm$,it forms methanol $(CH_3OH)$:$2CH_4 + O_2 \xrightarrow{Cu / 523 \ K / 100 \ atm} 2CH_3OH$Thus,$Y = CH_3OH$.Therefore,$X = CH_2O$ and $Y = CH_3OH$.

Identify $X$ and $Y$ in the following reactions:
$CH_4 + O_2 \xrightarrow{Mo_2O_3 / \Delta} X$
$2CH_4 + O_2 \xrightarrow{Cu / 523 \ K / 100 \ atm} 2Y$

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Identify $X$ and $Y$ in the following reactions:$CH_4 + O_2 \xrightarrow{Mo_2O_3 / \Delta} X$$2CH_4 + O_2 \xrightarrow{Cu / 523 \ K / 100 \ atm} 2Y$