Identify X and Y in the following reaction:CH | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction proceeds in two steps:Step $1$: Electrophilic addition of $HBr$ to ethene $(CH_2=CH_2)$ gives bromoethane $(CH_3CH_2Br)$. Thus,$X = H

Vedclass · Accepted Answer

$HBr, NaI / 	ext{dry } CH_3COCH_3$

Vedclass · Answer

(A) The reaction proceeds in two steps:Step $1$: Electrophilic addition of $HBr$ to ethene $(CH_2=CH_2)$ gives bromoethane $(CH_3CH_2Br)$. Thus,$X = HBr$.Step $2$: Bromoethane reacts with $NaI$ in dry acetone to form iodoethane $(CH_3CH_2I)$ via the Finkelstein reaction. Thus,$Y = NaI / 	ext{dry } CH_3COCH_3$.Therefore,the correct reagents are $X = HBr$ and $Y = NaI / 	ext{dry } CH_3COCH_3$.

Identify $X$ and $Y$ in the following reaction:
$CH_2=CH_2 \xrightarrow[(i) X]{(ii) Y} CH_3CH_2I$

Similar Questions

Explain the preparation of alkyl halides by halogen exchange methods.

Which among the following reactions is used for the preparation of alkyl fluorides?

In the given reaction:
$CH_3-CH_2-COOH \xrightarrow[(ii) \ Br_2/\Delta]{(i) \ AgNO_3} [X]$
$[X]$ will be:

Alkyl halides can be converted into Grignard reagents by:

The preparation of alkyl halides in the laboratory is least preferred by:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Identify $X$ and $Y$ in the following reaction:$CH_2=CH_2 \xrightarrow[(i) X]{(ii) Y} CH_3CH_2I$