Identify [A] and [B] in the following reactio | vedclass

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(D) The radioactive decay process follows the conservation of mass number and atomic number.$1$. For $\beta$-decay: ${ }_{89}^{227} Ac \xrightarrow{-\

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$Th, Ra$

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(D) The radioactive decay process follows the conservation of mass number and atomic number.$1$. For $\beta$-decay: ${ }_{89}^{227} Ac \xrightarrow{-\beta} { }_{90}^{227} Th + { }_{-1}^{0} e$. Thus, $[A] = { }_{90}^{227} Th$.$2$. For $\alpha$-decay: ${ }_{90}^{227} Th \xrightarrow{-\alpha} { }_{88}^{223} Ra + { }_{2}^{4} He$. Thus, $[B] = { }_{88}^{223} Ra$.$3$. Further $\alpha$-decay: ${ }_{88}^{223} Ra \xrightarrow{-\alpha} { }_{86}^{219} Rn + { }_{2}^{4} He$. This confirms the sequence.Therefore, $[A]$ is ${ }_{90}^{227} Th$ and $[B]$ is ${ }_{88}^{223} Ra$.

Identify $[A]$ and $[B]$ in the following reaction sequence:
${ }_{89}^{227} Ac$ $\xrightarrow{-\beta} [A]$ $\xrightarrow{-\alpha} [B]$ $\xrightarrow{-\alpha} { }_{86}^{219} Rn$

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Identify $[A]$ and $[B]$ in the following reaction sequence:${ }_{89}^{227} Ac$ $\xrightarrow{-\beta} [A]$ $\xrightarrow{-\alpha} [B]$ $\xrightarrow{-\alpha} { }_{86}^{219} Rn$