Identify an aromatic compound A left( C_7H_8O | vedclass

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(B) The molecular formula $C_7H_8O$ corresponds to an aromatic compound. $1$. $Na$ metal test: $A$ positive test indicates the presence of an acidic h

Vedclass · Accepted Answer

$C_6H_5CH_2OH$

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(B) The molecular formula $C_7H_8O$ corresponds to an aromatic compound. $1$. $Na$ metal test: $A$ positive test indicates the presence of an acidic hydrogen (like in $-OH$ group). $2$. Neutral $FeCl_3$ test: $A$ negative test indicates the absence of a phenolic $-OH$ group. $3$. Lucas reagent test: $A$ positive test indicates the presence of an alcohol group (specifically,primary,secondary,or tertiary alcohol). Analyzing the options: - $C_6H_5OCH_3$ (Anisole) does not have an $-OH$ group,so it will not react with $Na$ metal. - $C_6H_5CH_2OH$ (Benzyl alcohol) has an alcoholic $-OH$ group. It reacts with $Na$ metal (positive),does not give a color with neutral $FeCl_3$ (negative,as it is not a phenol),and reacts with Lucas reagent (positive,as it is a primary alcohol). - $p-CH_3C_6H_4OH$ and $m-CH_3C_6H_4OH$ are cresols (phenols). They will give a positive test with neutral $FeCl_3$. Therefore,the compound $A$ is $C_6H_5CH_2OH$.

Identify an aromatic compound $A \left( C_7H_8O \right)$ which gives the following tests with the given reagents:

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