Identify the correct order of acidic strength | vedclass

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(A) The acidic strength of hydrocarbons depends on the $s$-character of the carbon atom involved in the $C-H$ bond. Greater $s$-character leads to hig

Vedclass · Accepted Answer

$CH_3-CH_3 < CH_2=CH_2 < CH \equiv CH$

Vedclass · Answer

(A) The acidic strength of hydrocarbons depends on the $s$-character of the carbon atom involved in the $C-H$ bond. Greater $s$-character leads to higher electronegativity of the carbon atom,which stabilizes the resulting conjugate base (carbanion) more effectively. $1$. In $CH_3-CH_3$ ($sp^3$ hybridized),the $s$-character is $25\%$. $2$. In $CH_2=CH_2$ ($sp^2$ hybridized),the $s$-character is $33.3\%$. $3$. In $CH \equiv CH$ ($sp$ hybridized),the $s$-character is $50\%$. Thus,the order of acidic strength is $CH_3-CH_3 < CH_2=CH_2 < CH \equiv CH$.

Identify the correct order of acidic strength for the following hydrocarbons:

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