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(A) The work done by a system during a chemical reaction is given by the formula $W = -P \Delta V = -\Delta n_g RT$,where $\Delta n_g$ is the change i

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$2 H_2 O_{2(\ell)} \rightarrow 2 H_2 O_{(\ell)} + O_{2_{(g)}}$

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(A) The work done by a system during a chemical reaction is given by the formula $W = -P \Delta V = -\Delta n_g RT$,where $\Delta n_g$ is the change in the number of moles of gaseous species.If $\Delta n_g > 0$,then $W If $\Delta n_g  0$ (work is done on the system).For option $A$: $\Delta n_g = 1 - 0 = 1$. Since $\Delta n_g > 0$,work is done by the system $(W For option $B$: $\Delta n_g = 0 - 2 = -2$. Since $\Delta n_g  0)$.For option $C$: $\Delta n_g = 2 - 2 = 0$. Since $\Delta n_g = 0$,$W = 0$.For option $D$: $\Delta n_g = 2 - 4 = -2$. Since $\Delta n_g  0)$.Therefore,the reaction exhibiting negative work done by the system is $2 H_2 O_{2(\ell)} \rightarrow 2 H_2 O_{(\ell)} + O_{2_{(g)}}$.

Identify from the following reactions the one that exhibits negative work done by the system.

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