Identify product Z in the following reaction | vedclass

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Question

(A) Step $1$: $CH_2=CH-CH_2Br$ undergoes nucleophilic substitution with $NaCN$ to form $CH_2=CH-CH_2CN$ $(Y)$. Step $2$: The reaction of nitrile $(Y)$

Vedclass · Accepted Answer

$CH_2=CH-CH_2-C(=O)-C_6H_5$

Vedclass · Answer

(A) Step $1$: $CH_2=CH-CH_2Br$ undergoes nucleophilic substitution with $NaCN$ to form $CH_2=CH-CH_2CN$ $(Y)$. Step $2$: The reaction of nitrile $(Y)$ with Grignard reagent $(C_6H_5MgBr)$ followed by acid hydrolysis $(H_3O^{+})$ yields a ketone. $CH_2=CH-CH_2Br + NaCN ightarrow CH_2=CH-CH_2CN$ $(Y)$ $CH_2=CH-CH_2CN + C_6H_5MgBr$ $\xrightarrow{	ext{ether}} CH_2=CH-CH_2-C(=NMgBr)-C_6H_5$ $\xrightarrow{H_3O^{+}} CH_2=CH-CH_2-C(=O)-C_6H_5$ $(Z)$

Identify product $Z$ in the following reaction sequence:
$CH_2=CH-CH_2Br$ $\xrightarrow{NaCN} Y$ $\xrightarrow[1. C_6H_5MgBr, \text{diethylether}]{2. H_3O^{+}} Z$

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Identify product $Z$ in the following reaction sequence: $CH_2=CH-CH_2Br$ $\xrightarrow{NaCN} Y$ $\xrightarrow[1. C_6H_5MgBr, \text{diethylether}]{2. H_3O^{+}} Z$