Identify product C in the following reaction | vedclass

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(B) $1$. Nitrobenzene reacts with $Sn+HCl$ (a reducing agent) to form aniline $(A)$: $C_6H_5NO_2 + 6[H] \xrightarrow{Sn+HCl} C_6H_5NH_2 + 2H_2O$$2$. A

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Phenol

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(B) $1$. Nitrobenzene reacts with $Sn+HCl$ (a reducing agent) to form aniline $(A)$: $C_6H_5NO_2 + 6[H] \xrightarrow{Sn+HCl} C_6H_5NH_2 + 2H_2O$$2$. Aniline $(A)$ reacts with nitrous acid $(HNO_2)$ at $0^{\circ}C-5^{\circ}C$ to form benzene diazonium chloride $(B)$: $C_6H_5NH_2 + HNO_2 + HCl \xrightarrow{0^{\circ}C-5^{\circ}C} C_6H_5N_2^+Cl^- + 2H_2O$$3$. Benzene diazonium chloride $(B)$ on heating with water undergoes hydrolysis to form phenol $(C)$: $C_6H_5N_2^+Cl^- + H_2O \xrightarrow{\Delta} C_6H_5OH + N_2 + HCl$Therefore,the product $C$ is phenol.

Identify product $C$ in the following reaction sequence:
Nitrobenzene $\xrightarrow{Sn+HCl} A$ $\xrightarrow{HNO_2, 0^{\circ}C-5^{\circ}C} B$ $\xrightarrow{H_2O, \Delta} C$

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Identify product $C$ in the following reaction sequence:Nitrobenzene $\xrightarrow{Sn+HCl} A$ $\xrightarrow{HNO_2, 0^{\circ}C-5^{\circ}C} B$ $\xrightarrow{H_2O, \Delta} C$