Identify product B in the following reaction: | vedclass

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(D) The reaction proceeds as follows:$1$. $Aniline$ reacts with $NaNO_2 + HCl$ at $273 \ K$ to form $Benzenediazonium \ chloride$ $(A)$.$C_6H_5NH_2 +

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Phenol

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(D) The reaction proceeds as follows:$1$. $Aniline$ reacts with $NaNO_2 + HCl$ at $273 \ K$ to form $Benzenediazonium \ chloride$ $(A)$.$C_6H_5NH_2 + NaNO_2 + 2HCl \xrightarrow{273 \ K} C_6H_5N_2^+Cl^- + NaCl + 2H_2O$$2$. $Benzenediazonium \ chloride$ $(A)$ on heating with water $(H_2O, \Delta)$ undergoes hydrolysis to form $Phenol$ $(B)$ and releases $N_2$ gas.$C_6H_5N_2^+Cl^- + H_2O \xrightarrow{\Delta} C_6H_5OH + N_2 \uparrow + HCl$Therefore,product $B$ is $Phenol$.

Identify product $B$ in the following reaction: $Aniline$ $\xrightarrow{NaNO_2 + HCl, 273 \ K} A$ $\xrightarrow{H_2O, \Delta} B + N_2 \uparrow$

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