Identify substrate 'S' in the following react | vedclass

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(C) $1$. The reaction is the Wurtz reaction, where an alkyl halide reacts with $Na$ in dry ether to form a symmetric alkane by coupling two alkyl radi

Vedclass · Accepted Answer

$3-	ext{chloro}-3-	ext{methylpentane}$

Vedclass · Answer

(C) $1$. The reaction is the Wurtz reaction, where an alkyl halide reacts with $Na$ in dry ether to form a symmetric alkane by coupling two alkyl radicals.$2$. The product is $3, 4-	ext{diethyl}-3, 4-	ext{dimethylhexane}$. The structure is a symmetric alkane with a total of $14$ carbon atoms.$3$. To find the substrate '$S$', we split the product at the bond formed between the two alkyl groups. The bond is between $C3$ and $C4$ of the hexane chain.$4$. Splitting the molecule gives two identical units of $3-	ext{chloro}-3-	ext{methylpentane}$.$5$. Thus, the substrate '$S$' is $3-	ext{chloro}-3-	ext{methylpentane}$.

Identify substrate '$S$' in the following reaction: $S \xrightarrow{Na / \text{dry ether}} 3, 4-\text{diethyl}-3, 4-\text{dimethylhexane}$

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