Identify the alkyne in the following sequence | vedclass

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(A) $1$. The Wacker process converts ethene $(	ext{CH}_2=	ext{CH}_2)$ to ethanal $(	ext{CH}_3	ext{CHO})$,so $B$ is $	ext{CH}_3	ext{CHO}$.$2$. Oz

Vedclass · Accepted Answer

$H_3C-C \equiv C-CH_3$

Vedclass · Answer

(A) $1$. The Wacker process converts ethene $(	ext{CH}_2=	ext{CH}_2)$ to ethanal $(	ext{CH}_3	ext{CHO})$,so $B$ is $	ext{CH}_3	ext{CHO}$.$2$. Ozonolysis of an alkene $A$ yields $B$ (ethanal). Since $A \xrightarrow{	ext{O}_3} 2 	ext{CH}_3	ext{CHO}$,$A$ must be but$-2-$ene $(	ext{CH}_3	ext{CH}=	ext{CHCH}_3)$.$3$. The alkyne is reduced to $A$ (cis-but$-2-$ene) using Lindlar's catalyst. Therefore,the starting alkyne is but$-2-$yne $(	ext{CH}_3	ext{C} \equiv 	ext{CCH}_3)$.

Identify the alkyne in the following sequence of reactions:
Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$
Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.

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Identify the alkyne in the following sequence of reactions:Alkyne $\xrightarrow{\text{H}_2, \text{Lindlar's catalyst}} A$ $\xrightarrow{\text{Ozonolysis}} B \text{ (only)}$Given that $B$ is obtained from $\text{CH}_2=\text{CH}_2$ via the Wacker process.