Identify the bond order of NO^{+} ion. | vedclass

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(C) The total number of electrons in $NO^{+}$ is $7 (N) + 8 (O) - 1 = 14$ electrons. According to Molecular Orbital Theory,the electronic configuratio

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$3$

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(C) The total number of electrons in $NO^{+}$ is $7 (N) + 8 (O) - 1 = 14$ electrons. According to Molecular Orbital Theory,the electronic configuration of $NO^{+}$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2$. The bond order is calculated as: $	ext{Bond Order} = \frac{N_b - N_a}{2} = \frac{10 - 4}{2} = \frac{6}{2} = 3$.

Identify the bond order of $NO^{+}$ ion.

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