Identify the complex having the highest number of unpaired electrons from the following:

  • A
    $[Co(NH_3)_6]^{3+}$
  • B
    $[CoF_6]^{3-}$
  • C
    $[NiCl_4]^{2-}$
  • D
    $[Ni(CN)_4]^{2-}$

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Similar Questions

Match the List-$I$ with List-$II$
List-$I$ (Molecules/ion)List-$II$ (Hybridisation of central atom)
$A. PF_5$$I. dsp^2$
$B. SF_6$$II. sp^3d$
$C. Ni(CO)_4$$III. sp^3d^2$
$D. [PtCl_4]^{2-}$$IV. sp^3$
Choose the correct answer from the options given below $:$

Match the following:
List-$I$ (Hybridisation)List-$II$ (Compound/ion)
$A. sp^3d$$I. [PtCl_4]^{2-}$
$B. sp^3d^2$$II. SF_6$
$C. dsp^2$$III. BCl_3$
$D. dsp^3$$IV. PCl_5$
$V. ClF_3$

The correct match is:

The $d$-electronic configuration of an octahedral $Co(II)$ complex having magnetic moment of $3.95 \ BM$ is :

The one that can exhibit the highest paramagnetic behaviour among the following is:-
$gly = \text{glycinato}$; $bpy = 2,2'-\text{bipyridine}$

Nickel $(Z = 28)$ combines with a uninegative monodentate ligand to form a diamagnetic complex $[NiL_4]^{2-}$. The hybridisation involved and the number of unpaired electrons present in the complex are respectively

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