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(C) To find the $d$-configuration of the central metal ion, we determine the oxidation state of the metal in each complex:$(A)$ In $[FeO_4]^{2-}$, $Fe

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$(B)$ and $(D)$ only

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(C) To find the $d$-configuration of the central metal ion, we determine the oxidation state of the metal in each complex:$(A)$ In $[FeO_4]^{2-}$, $Fe + 4(-2) = -2 \implies Fe = +6$. $Fe^{6+} = [Ar] 3d^2$.$(B)$ In $[Mn(CN)_6]^{3-}$, $Mn + 6(-1) = -3 \implies Mn = +3$. $Mn^{3+} = [Ar] 3d^4$.$(C)$ In $[Fe(CN)_6]^{3-}$, $Fe + 6(-1) = -3 \implies Fe = +3$. $Fe^{3+} = [Ar] 3d^5$.$(D)$ In $[Cr(H_2O)_6]^{2+}$, $Cr + 6(0) = +2 \implies Cr = +2$. $Cr^{2+} = [Ar] 3d^4$.$(E)$ In $[NiF_6]^{2-}$, $Ni + 6(-1) = -2 \implies Ni = +4$. $Ni^{4+} = [Ar] 3d^6$.The complexes with $d^4$ configuration are $(B)$ and $(D)$.

$A. sp^3$	$(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$	$(ii). [Ni(CO)_4]$
$C. sp^3d^2$	$(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$	$(iv). [CoF_6]^{3-}$
	$(v). [Fe(CO)_5]$

Identify the coordination complexes in which the central metal ion has $d^4$ configuration.
$(A)$ $[FeO_4]^{2-}$
$(B)$ $[Mn(CN)_6]^{3-}$
$(C)$ $[Fe(CN)_6]^{3-}$
$(D)$ $[Cr(H_2O)_6]^{2+}$
$(E)$ $[NiF_6]^{2-}$
Choose the correct answer from the options given below:

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Match the following hybridization in Column $I$ with the corresponding coordination complexes in Column $II$.
$A. sp^3$ $(i). [Co(NH_3)_6]^{3+}$
$B. dsp^2$ $(ii). [Ni(CO)_4]$
$C. sp^3d^2$ $(iii). [Pt(NH_3)_2Cl_2]$
$D. d^2sp^3$ $(iv). [CoF_6]^{3-}$
$(v). [Fe(CO)_5]$

According to Werner’s theory,the geometry of the complex is determined by:

Select the option with the correct property -

Which of the following is not a square planar complex?

Considering that $\Delta_{0} > P$,the magnetic moment (in $BM$) of $[Ru(H_{2}O)_{6}]^{2+}$ would be

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Identify the coordination complexes in which the central metal ion has $d^4$ configuration.$(A)$ $[FeO_4]^{2-}$$(B)$ $[Mn(CN)_6]^{3-}$$(C)$ $[Fe(CN)_6]^{3-}$$(D)$ $[Cr(H_2O)_6]^{2+}$$(E)$ $[NiF_6]^{2-}$Choose the correct answer from the options given below: