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(C) In the first reaction,benzene reacts with $Cl_2$ in the presence of a Lewis acid catalyst $(AlCl_3)$ to undergo electrophilic aromatic substitutio

Vedclass · Accepted Answer

$A$ is aromatic but $B$ is non-aromatic

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(C) In the first reaction,benzene reacts with $Cl_2$ in the presence of a Lewis acid catalyst $(AlCl_3)$ to undergo electrophilic aromatic substitution,resulting in the formation of hexachlorobenzene $(C_6Cl_6)$,which is aromatic.In the second reaction,benzene reacts with excess $Cl_2$ in the presence of ultraviolet light $(h
u)$,which leads to electrophilic addition across the double bonds,forming benzene hexachloride ($C_6H_6Cl_6$,also known as gammaxene or lindane). This product is non-aromatic because the conjugation of the benzene ring is destroyed.Therefore,$A$ is aromatic and $B$ is non-aromatic.

Identify the correct statement regarding the products $A$ and $B$ formed in the following reactions of benzene:
$1$. Benzene + $6Cl_2$ $\xrightarrow{AlCl_3 \text{ (excess)}}$ $A$
$2$. Benzene + $Cl_2$ (excess) $\xrightarrow{h\nu, 500 \ K}$ $B$

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Identify the correct statement regarding the products $A$ and $B$ formed in the following reactions of benzene:$1$. Benzene + $6Cl_2$ $\xrightarrow{AlCl_3 \text{ (excess)}}$ $A$$2$. Benzene + $Cl_2$ (excess) $\xrightarrow{h\nu, 500 \ K}$ $B$