Identify the correct statements from the foll | vedclass

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(A) $Ti = [Ar] 3d^2 4s^2$ $Ti^{3+} = [Ar] 3d^1 4s^0$ $Ti^{4+} = [Ar] 3d^0 4s^0$ Since $Ti^{4+}$ has a vacant $d$-orbital and it acquires the nearest n

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$i, ii$ only

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(A) $Ti = [Ar] 3d^2 4s^2$ $Ti^{3+} = [Ar] 3d^1 4s^0$ $Ti^{4+} = [Ar] 3d^0 4s^0$ Since $Ti^{4+}$ has a vacant $d$-orbital and it acquires the nearest noble gas configuration,it is more stable compared to $Ti^{3+}$ and $Ti^{2+}$. $Cu^{2+} / Cu = +0.34 \ V$ has an exceptionally positive reduction potential among $3d$ series elements. $Sc$ shows $+3$ oxidation state and $Zn$ shows $+2$ oxidation state. They do not exhibit $+1$ oxidation state. Therefore,only $(i)$ and $(ii)$ are correct.

Identify the correct statements from the following: $(i)$ $Ti(IV)$ is more stable than $Ti(III)$ and $Ti(II)$ $(ii)$ Among $3d-$series elements (from $Z=22$ to $29$) only copper has positive reduction potential $(M^{2+} / M)$ $(iii)$ Both $Sc$ and $Zn$ exhibit $+1$ oxidation state

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