Identify the diamagnetic octahedral complex i | vedclass

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(D) To determine if a complex is diamagnetic,we check the electronic configuration of the central metal ion and the effect of the ligand field strengt

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$B$ and $C$ Only

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(D) To determine if a complex is diamagnetic,we check the electronic configuration of the central metal ion and the effect of the ligand field strength on the $d$-orbital splitting.$1$. $[Mn(CN)_6]^{3-}$: $Mn^{3+}$ is $3d^4$. $CN^-$ is a strong field ligand,causing pairing. Configuration: $t_{2g}^4 e_g^0$. It has two unpaired electrons,so it is paramagnetic.$2$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand. Configuration: $t_{2g}^6 e_g^0$. All electrons are paired,so it is diamagnetic.$3$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand. Configuration: $t_{2g}^6 e_g^0$. All electrons are paired,so it is diamagnetic.$4$. $[Co(H_2O)_3F_3]$: $Co^{3+}$ is $3d^6$. $H_2O$ and $F^-$ are weak field ligands. Configuration: $t_{2g}^4 e_g^2$. It has unpaired electrons,so it is paramagnetic.Thus,$B$ and $C$ are diamagnetic.

Identify the diamagnetic octahedral complex ions from below $:$
$A. [Mn(CN)_6]^{3-}$
$B. [Co(NH_3)_6]^{3+}$
$C. [Fe(CN)_6]^{4-}$
$D. [Co(H_2O)_3F_3]$
Choose the correct answer from the options given below $:$

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Identify the diamagnetic octahedral complex ions from below $:$$A. [Mn(CN)_6]^{3-}$$B. [Co(NH_3)_6]^{3+}$$C. [Fe(CN)_6]^{4-}$$D. [Co(H_2O)_3F_3]$Choose the correct answer from the options given below $:$