Identify the element if its expected electronic configuration is $[Ar] 3d^{10} 4s^{2}$.

The value of the azimuthal quantum number for electrons present in the $4p$ orbital is:

If $Br^{-}$ configuration is $[Ar]\, 3d^{10}\,4s^2\,4p^6$,then $Br^{+2}$ configuration will be identical to which element?

Which one is the correct outer electronic configuration of chromium $(Cr)$?

Given below are two statements:
Statement $I$ : For a given shell,the total number of allowed orbitals is given by $n^2$.
Statement $II$ : For any subshell,the spatial orientation of the orbitals is given by $-l$ to $+l$ values including zero.
In the light of the above statements,choose the correct answer from the options given below:

The probability of finding an electron in the $d_{xy}$ orbital is maximum along: