Identify the elements $x$ and $z$ in the following representation. $(Sb = \text{antimony})$

Match the following:

List-$I$ (Symbol of element)	List-$II$ (Group number)
$A$. $Mc$	$I$. $16$
$B$. $Lv$	$II$. $17$
$C$. $Fl$	$III$. $15$
$D$. $Ts$	$IV$. $14$

The correct answer is:

Determine the position of the element in the periodic table for the following outer electronic configurations:
$(i)$ $ns^2 np^4$ where $n = 3$
$(ii)$ $(n-1)d^2 ns^2$ where $n = 4$
$(iii)$ $(n-2)f^7 (n-1)d^1 ns^2$ where $n = 6$

The element with atomic number $36$ belongs to $\dots$ block in the periodic table.

The electronic configuration of an element $M$ is given below: $M: 1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10} 4f^2 5s^2 5p^6 5d^{10} 5f^0 6s^2$. Choose the correct information regarding the element $M$ for its period number,block and group number respectively.

Prove that according to quantum numbers,the $6^{th}$ period contains $32$ elements.