(B) Vanillin $(4\text{-hydroxy-}3\text{-methoxybenzaldehyde})$ is an organic compound with the molecular formula $C_8H_8O_3$.Structurally, it contains

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(B) Vanillin $(4\text{-hydroxy-}3\text{-methoxybenzaldehyde})$ is an organic compound with the molecular formula $C_8H_8O_3$.Structurally, it contains an aldehyde group $(-CHO)$, a phenolic hydroxyl group $(-OH)$, and a methoxy group $(-OCH_3)$ attached to a benzene ring.Thus, the correct set of functional groups is $-CHO, -OH, -OCH_3$.

Class 12 Chemistry 8-1.Aldehydes and Ketones Introduction

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Identify the functional group present in Vanillin.

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A
$-COOH, -OH, -OC_2H_5$
B
$-CHO, -OH, -OCH_3$
C
$-COOH, -CH_3, -OCH_3$
D
$-CHO, -OH, -OC_2H_5$

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8-1.Aldehydes and Ketones

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Introduction

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Match the formulas in column-$I$ with their corresponding names or functional group classifications in column-$II$.

column-$I$ column-$II$

$(i)$ $CH_3COCH_3$ $(a)$ Aldehyde,$(b)$ Ketone

$(ii)$ $CH_3CH_2CHO$ $(c)$ Propanone,$(d)$ Oxo

$(iii)$ $CH_3CH_2COOH$ $(e)$ One,$(f)$ al

$(g)$ Propanoic acid

column-$I$	column-$II$
$(i)$ $CH_3COCH_3$	$(a)$ Aldehyde,$(b)$ Ketone
$(ii)$ $CH_3CH_2CHO$	$(c)$ Propanone,$(d)$ Oxo
$(iii)$ $CH_3CH_2COOH$	$(e)$ One,$(f)$ al
	$(g)$ Propanoic acid