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(C) The rules for quantum numbers are: $1$. The principal quantum number '$n$' can be any positive integer $(1, 2, 3, \dots)$. $2$. The azimuthal quan

Vedclass · Accepted Answer

$n=3, l=3, m=1, s=\frac{1}{2}$

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(C) The rules for quantum numbers are: $1$. The principal quantum number '$n$' can be any positive integer $(1, 2, 3, \dots)$. $2$. The azimuthal quantum number '$l$' can have values from $0$ to $(n-1)$. $3$. The magnetic quantum number '$m$' can have values from $-l$ to $+l$ including $0$. $4$. The spin quantum number '$s$' can be $\pm\frac{1}{2}$. In option $C$, $n=3$, so the maximum value of '$l$' is $(n-1) = 2$. Since the given value is $l=3$, which is not possible for $n=3$, this set is impossible.

Identify the impossible quantum number set for an electron from the following:

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