Identify the isoelectronic pair from the foll | vedclass

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(A) Isoelectronic species are those that have the same number of electrons.$1$. For $Ne$ $(Z=10)$: Electrons = $10$. For $O^{2-}$ $(Z=8)$: Electrons =

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$Ne$ and $O^{2-}$

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(A) Isoelectronic species are those that have the same number of electrons.$1$. For $Ne$ $(Z=10)$: Electrons = $10$. For $O^{2-}$ $(Z=8)$: Electrons = $8 + 2 = 10$. Both have $10$ electrons,so they are isoelectronic.$2$. For $Cl^{-}$ $(Z=17)$: Electrons = $17 + 1 = 18$. For $Ca$ $(Z=20)$: Electrons = $20$. Not isoelectronic.$3$. For $Ar$ $(Z=18)$: Electrons = $18$. For $F^{-}$ $(Z=9)$: Electrons = $9 + 1 = 10$. Not isoelectronic.$4$. For $K^{+}$ $(Z=19)$: Electrons = $19 - 1 = 18$. For $Al^{3+}$ $(Z=13)$: Electrons = $13 - 3 = 10$. Not isoelectronic.Therefore,the correct pair is $Ne$ and $O^{2-}$.

Identify the isoelectronic pair from the following.

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