Class 12Chemistry8-2.Carboxylic acids and Their derivativeProperties of Carboxylic Acids and Their Derivatives
EasyIdentify the major product of the given reaction:
$C_6H_5COOH + Br_2 \xrightarrow{FeBr_3} \text{Product}$
$C_6H_5COOH + Br_2 \xrightarrow{FeBr_3} \text{Product}$
- ABenzoyl bromide
- BBromobenzene
- C$4-$bromo benzoic acid
- D$3-$bromo benzoic acid
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Similar Questions
$HOOC-(CH_2)_n-COOH \xrightarrow[\Delta]{} \text{product}$
At what value of $(n)$ will the given compound not evolve $CO_2$ gas?
At what value of $(n)$ will the given compound not evolve $CO_2$ gas?
Difficult
View SolutionGive reactions of carboxylic acids in which $C-OH$ bond breaks. $OR$ Give methods of preparation for $(a)$ anhydride $(b)$ ester $(c)$ acid chloride and $(d)$ amide from carboxylic acids.
Medium
View SolutionIn the given reaction :
$CH_3-COOH$ $\mathop{\xrightarrow{(i) Br_2/P}}_{(ii) NaCN, (iii) H_2O/H^{+}/\Delta}$ $[X]$
$[X]$ will be :
$CH_3-COOH$ $\mathop{\xrightarrow{(i) Br_2/P}}_{(ii) NaCN, (iii) H_2O/H^{+}/\Delta}$ $[X]$
$[X]$ will be :
Difficult
View SolutionThe major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$
In which of the following reactions will cyanide be obtained as the major product?
Difficult
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