Identify the pair of reactants that upon reac | vedclass

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Question

(A) To form the dipeptide $Gly-Ala$ (Glycyl-Alanine),the amino group $(-NH_2)$ of the second amino acid $(Alanine)$ must attack the activated carboxyl

Vedclass · Accepted Answer

$NH_2-CH_2-COCl$ and $NH_2-CH(CH_3)-COOH$

Vedclass · Answer

(A) To form the dipeptide $Gly-Ala$ (Glycyl-Alanine),the amino group $(-NH_2)$ of the second amino acid $(Alanine)$ must attack the activated carboxyl group $(-COCl)$ of the first amino acid $(Glycine)$. $Glycine$ is $NH_2-CH_2-COOH$. Its activated form is $NH_2-CH_2-COCl$. $Alanine$ is $NH_2-CH(CH_3)-COOH$. The reaction proceeds as follows: $NH_2-CH_2-COCl + NH_2-CH(CH_3)-COOH \rightarrow NH_2-CH_2-CONH-CH(CH_3)-COOH + HCl$. Thus,the correct pair of reactants is $NH_2-CH_2-COCl$ and $NH_2-CH(CH_3)-COOH$.

Amino acid	$pH$ at Isoelectric point
$(Amino \ acid)_{I}$	$6$
$(Amino \ acid)_{II}$	$9.8$
$(Amino \ acid)_{III}$	$3.9$

Identify the pair of reactants that upon reaction,with elimination of $HCl$,will give rise to the dipeptide $Gly-Ala$.

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The $pH$ at the isoelectric point of three amino acids are given as follows:

Amino acid $pH$ at Isoelectric point

$(Amino \ acid)_{I}$ $6$

$(Amino \ acid)_{II}$ $9.8$

$(Amino \ acid)_{III}$ $3.9$

$(Amino \ acid)_{II}$ is . . . . . . ?

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