Identify the product $Z$ in the following reaction:
$C_6H_5NH_2$ $\xrightarrow{(Ac)_2O} X$ $\xrightarrow{Br_2/CCl_4} Y$ $\xrightarrow{HOH} Z$

Which of the following compounds reacts with chloroform and a base to form phenyl isocyanide?

The reagent$(s)$ used for the conversion of benzene diazonium hydrogensulphate to benzene is/are:

$CH_3NH_2 + CHCl_3 + KOH \rightarrow$ Nitrogen containing compound $+ KCl + H_2O$. The nitrogen-containing compound is:

The strongest conjugate acid will result from:

Decarboxylation of all six possible isomers of diaminobenzoic acids $C_6H_3(NH_2)_2COOH$ yields three products $A, B$ and $C$. Three acids give product $A$,two acids give product $B$ and one acid gives product $C$. The melting point of product $C$ is .....$^{\circ} C$.