Identify the product B in the following serie | vedclass

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(B) Step $1$: Dehydration of $CH_3-CH_2-CH_2-OH$ (Propan$-1-$ol) with $Al_2 O_3$ at $623 \ K$ gives $A$,which is Propene $(CH_3-CH=CH_2)$.Step $2$: Pr

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Propan$-2-$ol

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(B) Step $1$: Dehydration of $CH_3-CH_2-CH_2-OH$ (Propan$-1-$ol) with $Al_2 O_3$ at $623 \ K$ gives $A$,which is Propene $(CH_3-CH=CH_2)$.Step $2$: Propene reacts with conc. $H_2 SO_4$ followed by hydrolysis $(H_2 O)$ to undergo hydration according to Markovnikov's rule.Step $3$: The reaction follows the mechanism: $CH_3-CH=CH_2 + H_2 SO_4$ $\rightarrow CH_3-CH(OSO_3 H)-CH_3$ $\xrightarrow{H_2 O} CH_3-CH(OH)-CH_3$ (Propan$-2-$ol).Thus,the product $B$ is Propan$-2-$ol.

Identify the product $B$ in the following series of reactions.
$CH_3-CH_2-CH_2-OH$ $\xrightarrow{Al_2 O_3, 623 \ K} A$ $\xrightarrow[(ii) H_2 O]{(i) \text{conc. } H_2 SO_4} B$

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Identify the product $B$ in the following series of reactions.$CH_3-CH_2-CH_2-OH$ $\xrightarrow{Al_2 O_3, 623 \ K} A$ $\xrightarrow[(ii) H_2 O]{(i) \text{conc. } H_2 SO_4} B$