Identify the product formed when 2-Bromobutan | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) When $2-$Bromobutane $(CH_3CH(Br)CH_2CH_3)$ is treated with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes a nucleophilic substitut

Vedclass · Accepted Answer

Butan$-2-$ol

Vedclass · Answer

(D) When $2-$Bromobutane $(CH_3CH(Br)CH_2CH_3)$ is treated with an aqueous solution of sodium hydroxide $(NaOH)$,it undergoes a nucleophilic substitution reaction ($S_N1$ or $S_N2$ mechanism depending on conditions,but typically $S_N2$ for secondary halides in aqueous media). The hydroxide ion $(OH^-)$ acts as a nucleophile and replaces the bromide ion $(Br^-)$. The reaction is: $CH_3CH(Br)CH_2CH_3 + NaOH_{(aq)} \rightarrow CH_3CH(OH)CH_2CH_3 + NaBr$. The product formed is Butan$-2-$ol.

Identify the product formed when $2-$Bromobutane is heated with aqueous solution of sodium hydroxide.

Similar Questions

Identify the compound that undergoes $S_{N}1$ mechanism most rapidly.

$A$ compound $A$ $(C_5H_{10}Cl_2)$ on hydrolysis gives $C_5H_{10}O$ which reacts with $NH_2OH$,forms iodoform,but does not give Fehling's test. $A$ is:

The products $A$ and $B$ in the following reactions,respectively,are:
$A \xleftarrow{AgNO_2} CH_3-CH_2-CH_2-Br \xrightarrow{AgCN} B$

Alcoholic solution of $KOH$ is used for

The dehydrohalogenation of neopentyl bromide with alcoholic $KOH$ mainly gives

Vedclass Test Series

Exam Paper Generator

Online Exam Module