Identify the product obtained when sucrose is | vedclass

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(D) Sucrose is a disaccharide with the formula $C_{12}H_{22}O_{11}$.When treated with concentrated $H_2SO_4$,it undergoes dehydration.The concentrated

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Sugar charcoal and water

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(D) Sucrose is a disaccharide with the formula $C_{12}H_{22}O_{11}$.When treated with concentrated $H_2SO_4$,it undergoes dehydration.The concentrated $H_2SO_4$ acts as a strong dehydrating agent and removes water molecules from the sucrose.The reaction is: $C_{12}H_{22}O_{11} \xrightarrow{	ext{conc. } H_2SO_4} 12C + 11H_2O$.Thus,the products obtained are sugar charcoal $(12C)$ and water $(11H_2O)$.

List-$I$ (Carbohydrate)	List-$II$ (Linkage Source)
$A$. Amylose	$I$. $\beta-C_1-C_4$,plant
$B$. Cellulose	$II$. $\alpha-C_1-C_4$,animal
$C$. Glycogen	$III$. $\alpha-C_1-C_4, \alpha-C_1-C_6$,plant
$D$. Amylopectin	$IV$. $\alpha-C_1-C_4$,plant

Identify the product obtained when sucrose is treated with conc. $H_2 SO_4$.

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