Identify the products (X, Y) and reaction mec | vedclass

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(A) $(i)$ The reaction of an ether with $HI$ produces an alcohol and an alkyl iodide. In the presence of a $3^{\circ}$ carbon atom in one of the alkyl

Vedclass · Accepted Answer

$X = CH_3CH_2OH, Y = (CH_3)_2(CH_3CH_2)C-I, Z = S_N1$

Vedclass · Answer

(A) $(i)$ The reaction of an ether with $HI$ produces an alcohol and an alkyl iodide. In the presence of a $3^{\circ}$ carbon atom in one of the alkyl groups of the ether,the iodide ion $(-I)$ attacks the more substituted carbon atom (the $3^{\circ}$ carbon) via the $S_N1$ mechanism.$(ii)$ This occurs because the $3^{\circ}$ carbocation formed during the reaction is highly stable compared to $1^{\circ}$ or $2^{\circ}$ carbocations,and the $S_N2$ mechanism is hindered by significant steric hindrance at the $3^{\circ}$ carbon.$(iii)$ In the given reaction,the ether is $2-ethoxy-2-methylbutane$. The $HI$ cleaves the bond between the oxygen and the $3^{\circ}$ carbon,leading to the formation of ethanol $(CH_3CH_2OH)$ and $2-iodo-2-methylbutane$ $((CH_3)_2(CH_3CH_2)C-I)$ via the $S_N1$ mechanism.Thus,option $A$ is the correct answer.

Identify the products $(X, Y)$ and reaction mechanism $(Z)$ of the following reaction:
$CH_3CH_2-O-C(CH_3)_2CH_2CH_3 \xrightarrow{HI, \Delta} X + Y$

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Identify the products $(X, Y)$ and reaction mechanism $(Z)$ of the following reaction:$CH_3CH_2-O-C(CH_3)_2CH_2CH_3 \xrightarrow{HI, \Delta} X + Y$