(C) The reaction $C_6H_5COOC_2H_5 \xrightarrow{\text{dil. } H_2SO_4} ?$ represents the acidic hydrolysis of an ester.In acidic hydrolysis,an ester rea

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(C) The reaction $C_6H_5COOC_2H_5 \xrightarrow{\text{dil. } H_2SO_4} ?$ represents the acidic hydrolysis of an ester.In acidic hydrolysis,an ester reacts with water in the presence of an acid catalyst (like $dil. H_2SO_4$) to produce a carboxylic acid and an alcohol.The general reaction is: $RCOOR' + H_2O \xrightarrow{H^+} RCOOH + R'OH$.For the given ester,ethyl benzoate $(C_6H_5COOC_2H_5)$,the hydrolysis yields benzoic acid $(C_6H_5COOH)$ and ethanol $(C_2H_5OH)$.

Class 12 Chemistry 8-2.Carboxylic acids and Their derivative Properties of Carboxylic Acids and Their Derivatives

Medium

Identify the products of the following reaction:
$C_6H_5COOC_2H_5 \xrightarrow{\text{dil. } H_2SO_4} ?$

MHT CET 2021 All MHT CET

A
$C_6H_5OH + C_2H_5OH$
B
$C_6H_5COOH + C_2H_5COOH$
C
$C_6H_5COOH + C_2H_5OH$
D
$C_6H_5OH + C_2H_5COOH$

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8-2.Carboxylic acids and Their derivative

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Properties of Carboxylic Acids and Their Derivatives

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The decreasing order of acidic strength for the following acids is:
$(A)$ $CH_3COOH$
$(B)$ $CH_3CHClCH_2COOH$
$(C)$ $ClCH_2COOH$
$(D)$ $Cl_2CHCOOH$

EasyTS EAMCET 2019

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The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

MediumTS EAMCET 2021

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$CH_3COOH + C_2H_5^{18}OH \xrightarrow{Conc. H_2SO_4} (X)$
$CH_3COOH + (CH_3)_3C^{18}OH \xrightarrow{Conc. H_2SO_4} (Y)$
In the above reaction $(X)$ and $(Y)$ are respectively:

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An organic compound is boiled with alcoholic potash. The product is cooled and acidified with $HCl$,resulting in the precipitation of a white solid. What could be the starting compound?

Difficult

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Predict the product of the reaction:
$\text{2-oxocyclohexanecarboxylic acid} \xrightarrow[{(2)\Delta }]{{(1){H_3}{O^ + }}}$

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Identify the products of the following reaction:$C_6H_5COOC_2H_5 \xrightarrow{\text{dil. } H_2SO_4} ?$

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The decreasing order of acidic strength for the following acids is:$(A)$ $CH_3COOH$$(B)$ $CH_3CHClCH_2COOH$$(C)$ $ClCH_2COOH$$(D)$ $Cl_2CHCOOH$

The major product formed in the following reaction is$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

$CH_3COOH + C_2H_5^{18}OH \xrightarrow{Conc. H_2SO_4} (X)$ $CH_3COOH + (CH_3)_3C^{18}OH \xrightarrow{Conc. H_2SO_4} (Y)$ In the above reaction $(X)$ and $(Y)$ are respectively:

An organic compound is boiled with alcoholic potash. The product is cooled and acidified with $HCl$,resulting in the precipitation of a white solid. What could be the starting compound?

Predict the product of the reaction: $\text{2-oxocyclohexanecarboxylic acid} \xrightarrow[{(2)\Delta }]{{(1){H_3}{O^ + }}}$

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Identify the products of the following reaction:
$C_6H_5COOC_2H_5 \xrightarrow{\text{dil. } H_2SO_4} ?$

The decreasing order of acidic strength for the following acids is:
$(A)$ $CH_3COOH$
$(B)$ $CH_3CHClCH_2COOH$
$(C)$ $ClCH_2COOH$
$(D)$ $Cl_2CHCOOH$

The major product formed in the following reaction is
$C_6H_5CH=CH_2$ $\xrightarrow[(ii) H_3O^+]{(i) KMnO_4, KOH, \Delta}$ $\xrightarrow{(iii) Br_2/FeBr_3} \text{Product}$

$CH_3COOH + C_2H_5^{18}OH \xrightarrow{Conc. H_2SO_4} (X)$
$CH_3COOH + (CH_3)_3C^{18}OH \xrightarrow{Conc. H_2SO_4} (Y)$
In the above reaction $(X)$ and $(Y)$ are respectively:

Predict the product of the reaction:
$\text{2-oxocyclohexanecarboxylic acid} \xrightarrow[{(2)\Delta }]{{(1){H_3}{O^ + }}}$