Identify the reactions in which H_2 is libera | vedclass

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(A) $(i)$ $Zn + 2NaOH_{(aq)} \longrightarrow Na_2ZnO_2 + H_{2(g)}$ (Liberates $H_2$)$(ii)$ $HCOOH \xrightarrow[	ext{Conc. } H_2SO_4]{373 \ K} H_2O +

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$i, iii, iv, v$

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(A) $(i)$ $Zn + 2NaOH_{(aq)} \longrightarrow Na_2ZnO_2 + H_{2(g)}$ (Liberates $H_2$)$(ii)$ $HCOOH \xrightarrow[	ext{Conc. } H_2SO_4]{373 \ K} H_2O + CO$ (Does not liberate $H_2$)$(iii)$ $CH_{4(g)} + H_2O_{(g)} \xrightarrow[Ni]{1270 \ K} CO_{(g)} + 3H_{2(g)}$ (Liberates $H_2$)$(iv)$ $Zn + 2H^+_{(aq)} \longrightarrow Zn^{2+} + H_{2(g)}$ (Liberates $H_2$)$(v)$ $C_{(s)} + H_2O_{(g)} \xrightarrow{1270 \ K} CO_{(g)} + H_{2(g)}$ (Liberates $H_2$)Therefore,reactions $(i)$,$(iii)$,$(iv)$,and $(v)$ liberate $H_2$ gas.

List-$I$ (Type of hydride)	List-$II$ (Example)
$(A)$ Electron precise	$(i)$ $SiH_4$
$(B)$ Saline	$(ii)$ $H_2O$
$(C)$ Electron deficient	$(iii)$ $MgH_2$
$(D)$ Electron rich	$(iv)$ $B_2H_6$

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