Identify the reducing agent in the following reaction:
$CH_{4(g)} + 2O_{2(g)} \longrightarrow CO_{2(g)} + 2H_2O_{(l)}$

Which compound acts as an oxidising as well as reducing agent?

Which of the following cannot act as a reducing agent?

Why does the following reaction occur?
$XeO_6^{4-}{(aq)} + 2F^{-}{(aq)} + 6H^{+}{(aq)} \rightarrow XeO_{3_{(g)}} + F_{2_{(g)}} + 3H_2O_{(l)}$
What conclusion about the compound $Na_4XeO_6$ (of which $XeO_6^{4-}$ is a part) can be drawn from the reaction?

Identify the weakest oxidizing agent among the following.

$A$ compound is in its low oxidation state. Then it will be