Identify the site,where attack of H^{+} is mo | vedclass

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Question

(A) The molecule is $N$-methyl$-4-$pyridone. The nitrogen atom donates its lone pair into the ring,which causes the delocalization of electrons toward

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$a$

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(A) The molecule is $N$-methyl$-4-$pyridone. The nitrogen atom donates its lone pair into the ring,which causes the delocalization of electrons towards the oxygen atom. This results in a resonance structure where the oxygen atom carries a partial negative charge $(\delta^-)$ and the nitrogen atom carries a partial positive charge $(\delta^+)$. Due to the high electron density on the oxygen atom,it acts as the most basic site in the molecule. Therefore,the electrophilic $H^{+}$ ion will most favourably attack the oxygen atom at site $a$.

Identify the site,where attack of $H^{+}$ is most favourable.

Similar Questions

Correct statements for the given reaction are :
$A$. Compound '$B$' is aromatic
$B$. The completion of above reaction is very slow
$C$. '$A$' shows tautomerism
$D$. The bond lengths $C-C$ in compound $B$ are found to be same
Choose the correct answer from the options given below :

The correct order of stability for the given canonical structures is:
$(I)$ $H-C(=O)-CH_2^-$
$(II)$ $H-C(O^-)(^+)-CH_2^-$
$(III)$ $H-C(O^-)=CH_2$

Which of the following species does not exert a resonance effect?

The correct order of $C=O$ bond length in ethyl propanoate $(I)$, ethyl propenoate $(II)$ and ethenyl propanoate $(III)$ is

The most stable resonating structure is

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